本文主要关于python的正则表达式的符号与方法。

findall: 找寻所有匹配,返回所有组合的列表
search: 找寻第一个匹配并返回
sub: 替换符合规律的内容,并返回替换后的内容
.:匹配除了换行符以外的任意字符

a = 'xy123'
b = re.findall('x...',a)
print(b)
# ['xy12']

*:匹配前一个字符0次或者无限次

a = 'xyxy123'
b = re.findall('x*',a)
print(b)
# ['x', '', 'x', '', '', '', '', '']

"htmlcode">

a = 'xy123'
b = re.findall('x"htmlcode">
b = re.findall('xx.*xx',secret_code)
print(b)
# ['xxIxxfasdjifja134xxlovexx23345sdfxxyouxx']

.*"htmlcode">

c = re.findall('xx.*"htmlcode">
d = re.findall('xx(.*"htmlcode">
s = '''sdfxxhello
xxfsdfxxworldxxasdf'''

d = re.findall('xx(.*"htmlcode">
s2 = 'asdfxxIxx123xxlovexxdfd'
f = re.search('xx(.*"htmlcode">
s = '123rrrrr123'
output = re.sub('123(.*"htmlcode">
import re

def multiply(m):
  # Convert group 0 to an integer.
  v = m.group(0)
  print(v)
  # Multiply integer by 2.
  # ... Convert back into string and return it.
  print('basic/'+v)
  return 'basic/'+v

结果如下

>autoencoder.png
  basic/autoencoder.png
  RNN.png
  basic/RNN.png
  rnn_step_forward.png
  basic/rnn_step_forward.png
  rnns.png
  basic/rnns.png
  rnn_cell_backprop.png
  basic/rnn_cell_backprop.png
  LSTM.png
  basic/LSTM.png
  LSTM_rnn.png
  basic/LSTM_rnn.png
  attn_mechanism.png
  basic/attn_mechanism.png
  attn_model.png
  basic/attn_model.png

仿照上面案例,我们可以方便的对我们的任务进行定制。

subn相比sub,subn返回元组,第二个元素表示替换发生的次数:

import re

def add(m):
  # Convert.
  v = int(m.group(0))
  # Add 2.
  return str(v + 1)

# Call re.subn.
result = re.subn("\d+", add, "1 2 3 4 5")

print("Result string:", result[0])
print("Number of substitutions:", result[1])
>
Result string: 11 21 31 41 51
Number of substitutions: 5

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